Base | Representation |
---|---|
bin | 1011110111101000010110… |
… | …1101110011111100111111 |
3 | 1201012121020121110222212210 |
4 | 2331322011231303330333 |
5 | 3202304111112234010 |
6 | 43431125550031503 |
7 | 2514566636632002 |
oct | 275720555637477 |
9 | 51177217428783 |
10 | 13050354024255 |
11 | 4181695696479 |
12 | 15692b51a8593 |
13 | 738848b8cc42 |
14 | 3318d778d539 |
15 | 17970a15cb20 |
hex | bde85b73f3f |
13050354024255 has 32 divisors (see below), whose sum is σ = 21168837492480. Its totient is φ = 6864118606080.
The previous prime is 13050354024247. The next prime is 13050354024343. The reversal of 13050354024255 is 55242045305031.
It is not a de Polignac number, because 13050354024255 - 23 = 13050354024247 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9820500 + ... + 11069910.
It is an arithmetic number, because the mean of its divisors is an integer number (661526171640).
Almost surely, 213050354024255 is an apocalyptic number.
13050354024255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13050354024255 is a deficient number, since it is larger than the sum of its proper divisors (8118483468225).
13050354024255 is a wasteful number, since it uses less digits than its factorization.
13050354024255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1259031.
The product of its (nonzero) digits is 360000, while the sum is 39.
Adding to 13050354024255 its reverse (55242045305031), we get a palindrome (68292399329286).
The spelling of 13050354024255 in words is "thirteen trillion, fifty billion, three hundred fifty-four million, twenty-four thousand, two hundred fifty-five".
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