Base | Representation |
---|---|
bin | 1011110111101010110110… |
… | …1111010111110101111111 |
3 | 1201012122222102000121200101 |
4 | 2331322231233113311333 |
5 | 3202312000013201142 |
6 | 43431320334341531 |
7 | 2514622402363342 |
oct | 275725557276577 |
9 | 51178872017611 |
10 | 13051025522047 |
11 | 41819aa738727 |
12 | 156946205a8a7 |
13 | 738925030006 |
14 | 33195ca28459 |
15 | 1797490a00b7 |
hex | bdeadbd7d7f |
13051025522047 has 2 divisors, whose sum is σ = 13051025522048. Its totient is φ = 13051025522046.
The previous prime is 13051025521979. The next prime is 13051025522057. The reversal of 13051025522047 is 74022552015031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13051025522047 - 215 = 13051025489279 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13051025521997 and 13051025522015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13051025522057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6525512761023 + 6525512761024.
It is an arithmetic number, because the mean of its divisors is an integer number (6525512761024).
Almost surely, 213051025522047 is an apocalyptic number.
13051025522047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13051025522047 is an equidigital number, since it uses as much as digits as its factorization.
13051025522047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84000, while the sum is 37.
Adding to 13051025522047 its reverse (74022552015031), we get a palindrome (87073577537078).
The spelling of 13051025522047 in words is "thirteen trillion, fifty-one billion, twenty-five million, five hundred twenty-two thousand, forty-seven".
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