Base | Representation |
---|---|
bin | 111100110001100110… |
… | …1010001011010000011 |
3 | 110110212201001211020022 |
4 | 1321203031101122003 |
5 | 4114242420124220 |
6 | 135542420004055 |
7 | 12300146646035 |
oct | 1714315213203 |
9 | 413781054208 |
10 | 130513442435 |
11 | 50394488022 |
12 | 2136483062b |
13 | c3cc38531c |
14 | 646175dc55 |
15 | 35dce84925 |
hex | 1e63351683 |
130513442435 has 8 divisors (see below), whose sum is σ = 156618431280. Its totient is φ = 104409220384.
The previous prime is 130513442417. The next prime is 130513442447. The reversal of 130513442435 is 534244315031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130513442435 - 228 = 130245006979 is a prime.
It is a super-3 number, since 3×1305134424353 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130513442395 and 130513442404.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 295181 + ... + 590049.
It is an arithmetic number, because the mean of its divisors is an integer number (19577303910).
Almost surely, 2130513442435 is an apocalyptic number.
130513442435 is a deficient number, since it is larger than the sum of its proper divisors (26104988845).
130513442435 is an equidigital number, since it uses as much as digits as its factorization.
130513442435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 383397.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 130513442435 its reverse (534244315031), we get a palindrome (664757757466).
The spelling of 130513442435 in words is "one hundred thirty billion, five hundred thirteen million, four hundred forty-two thousand, four hundred thirty-five".
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