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130515024235 = 526399250969
BaseRepresentation
bin111100110001101001…
…1010011100101101011
3110110212211001012001111
41321203103103211223
54114243321233420
6135542513531151
712300166254511
oct1714323234553
9413784035044
10130515024235
11503953684a2
1221365273ab7
13c3cc7ba2bb
146461a524b1
1535dd19845a
hex1e634d396b

130515024235 has 8 divisors (see below), whose sum is σ = 157213536480. Its totient is φ = 104015014464.

The previous prime is 130515024217. The next prime is 130515024247. The reversal of 130515024235 is 532420515031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130515024235 - 213 = 130515016043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130515024197 and 130515024206.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49624170 + ... + 49626799.

It is an arithmetic number, because the mean of its divisors is an integer number (19651692060).

Almost surely, 2130515024235 is an apocalyptic number.

130515024235 is a deficient number, since it is larger than the sum of its proper divisors (26698512245).

130515024235 is an equidigital number, since it uses as much as digits as its factorization.

130515024235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99251237.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 130515024235 its reverse (532420515031), we get a palindrome (662935539266).

The spelling of 130515024235 in words is "one hundred thirty billion, five hundred fifteen million, twenty-four thousand, two hundred thirty-five".

Divisors: 1 5 263 1315 99250969 496254845 26103004847 130515024235