Base | Representation |
---|---|
bin | 11101101011010100001111… |
… | …011111001110111011100000 |
3 | 122010010120222200021101100000 |
4 | 131223110033133032323200 |
5 | 114101420000334112000 |
6 | 1141332023032500000 |
7 | 36330521536255155 |
oct | 3553241737167340 |
9 | 563116880241300 |
10 | 130520021004000 |
11 | 38651259230321 |
12 | 1277b7a2b4a600 |
13 | 57a9ca6552c94 |
14 | 24332ba3b422c |
15 | 10151d2be6000 |
hex | 76b50f7ceee0 |
130520021004000 has 1152 divisors, whose sum is σ = 484330567698432. Its totient is φ = 34519517798400.
The previous prime is 130520021003993. The next prime is 130520021004047. The reversal of 130520021004000 is 400120025031.
130520021004000 is a `hidden beast` number, since 1 + 3 + 0 + 52 + 0 + 0 + 210 + 0 + 400 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 133592651512 + ... + 133592652488.
It is an arithmetic number, because the mean of its divisors is an integer number (420425840016).
Almost surely, 2130520021004000 is an apocalyptic number.
130520021004000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130520021004000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (242165283849216).
130520021004000 is an abundant number, since it is smaller than the sum of its proper divisors (353810546694432).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130520021004000 is an equidigital number, since it uses as much as digits as its factorization.
130520021004000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2007 (or 1977 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 18.
Adding to 130520021004000 its reverse (400120025031), we get a palindrome (130920141029031).
The spelling of 130520021004000 in words is "one hundred thirty trillion, five hundred twenty billion, twenty-one million, four thousand".
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