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130521324113 = 1071219825459
BaseRepresentation
bin111100110001110101…
…1010101101001010001
3110110220020220020212022
41321203223111221101
54114301424332423
6135543300541225
712300303643505
oct1714353255121
9413806806768
10130521324113
1150398980704
12213673b1815
13c400bb493b
146462812305
1535dd9dedc8
hex1e63ad5a51

130521324113 has 4 divisors (see below), whose sum is σ = 131741149680. Its totient is φ = 129301498548.

The previous prime is 130521324013. The next prime is 130521324119. The reversal of 130521324113 is 311423125031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130521324113 - 214 = 130521307729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130521324119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 609912623 + ... + 609912836.

It is an arithmetic number, because the mean of its divisors is an integer number (32935287420).

Almost surely, 2130521324113 is an apocalyptic number.

It is an amenable number.

130521324113 is a deficient number, since it is larger than the sum of its proper divisors (1219825567).

130521324113 is a wasteful number, since it uses less digits than its factorization.

130521324113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1219825566.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 130521324113 its reverse (311423125031), we get a palindrome (441944449144).

The spelling of 130521324113 in words is "one hundred thirty billion, five hundred twenty-one million, three hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 107 1219825459 130521324113