Base | Representation |
---|---|
bin | 111100110001111010… |
… | …1100100000011000111 |
3 | 110110220102221102201210 |
4 | 1321203311210003013 |
5 | 4114303121121201 |
6 | 135543434222503 |
7 | 12300335506263 |
oct | 1714365440307 |
9 | 413812842653 |
10 | 130524004551 |
11 | 5039a441546 |
12 | 21368284a33 |
13 | c4016129b5 |
14 | 6462d0d0a3 |
15 | 35ddd6e1d6 |
hex | 1e63d640c7 |
130524004551 has 16 divisors (see below), whose sum is σ = 178089982560. Its totient is φ = 85001354880.
The previous prime is 130524004483. The next prime is 130524004553. The reversal of 130524004551 is 155400425031.
It is not a de Polignac number, because 130524004551 - 213 = 130523996359 is a prime.
It is a super-3 number, since 3×1305240045513 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130524004553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1755960 + ... + 1828781.
It is an arithmetic number, because the mean of its divisors is an integer number (11130623910).
Almost surely, 2130524004551 is an apocalyptic number.
130524004551 is a deficient number, since it is larger than the sum of its proper divisors (47565978009).
130524004551 is a wasteful number, since it uses less digits than its factorization.
130524004551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3585026.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 130524004551 its reverse (155400425031), we get a palindrome (285924429582).
The spelling of 130524004551 in words is "one hundred thirty billion, five hundred twenty-four million, four thousand, five hundred fifty-one".
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