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130524004551 = 3532293584741
BaseRepresentation
bin111100110001111010…
…1100100000011000111
3110110220102221102201210
41321203311210003013
54114303121121201
6135543434222503
712300335506263
oct1714365440307
9413812842653
10130524004551
115039a441546
1221368284a33
13c4016129b5
146462d0d0a3
1535ddd6e1d6
hex1e63d640c7

130524004551 has 16 divisors (see below), whose sum is σ = 178089982560. Its totient is φ = 85001354880.

The previous prime is 130524004483. The next prime is 130524004553. The reversal of 130524004551 is 155400425031.

It is not a de Polignac number, because 130524004551 - 213 = 130523996359 is a prime.

It is a super-3 number, since 3×1305240045513 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130524004553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1755960 + ... + 1828781.

It is an arithmetic number, because the mean of its divisors is an integer number (11130623910).

Almost surely, 2130524004551 is an apocalyptic number.

130524004551 is a deficient number, since it is larger than the sum of its proper divisors (47565978009).

130524004551 is a wasteful number, since it uses less digits than its factorization.

130524004551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3585026.

The product of its (nonzero) digits is 12000, while the sum is 30.

Adding to 130524004551 its reverse (155400425031), we get a palindrome (285924429582).

The spelling of 130524004551 in words is "one hundred thirty billion, five hundred twenty-four million, four thousand, five hundred fifty-one".

Divisors: 1 3 53 159 229 687 12137 36411 3584741 10754223 189991273 569973819 820905689 2462717067 43508001517 130524004551