Base | Representation |
---|---|
bin | 10010111111100110011… |
… | …100000010011000001011 |
3 | 11121210001111121000011211 |
4 | 102333212130002120023 |
5 | 132341113221401024 |
6 | 2435341452433551 |
7 | 163205044100302 |
oct | 22774634023013 |
9 | 4553044530154 |
10 | 1305241200139 |
11 | 4636056a2458 |
12 | 190b6a7788b7 |
13 | 96111c071b6 |
14 | 472616b5439 |
15 | 23e44123594 |
hex | 12fe670260b |
1305241200139 has 2 divisors, whose sum is σ = 1305241200140. Its totient is φ = 1305241200138.
The previous prime is 1305241200113. The next prime is 1305241200157. The reversal of 1305241200139 is 9310021425031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1305241200139 - 211 = 1305241198091 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1305241200139.
It is not a weakly prime, because it can be changed into another prime (1305241200239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652620600069 + 652620600070.
It is an arithmetic number, because the mean of its divisors is an integer number (652620600070).
Almost surely, 21305241200139 is an apocalyptic number.
1305241200139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305241200139 is an equidigital number, since it uses as much as digits as its factorization.
1305241200139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 31.
The spelling of 1305241200139 in words is "one trillion, three hundred five billion, two hundred forty-one million, two hundred thousand, one hundred thirty-nine".
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