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1305241200113 is a prime number
BaseRepresentation
bin10010111111100110011…
…100000010010111110001
311121210001111121000010212
4102333212130002113301
5132341113221400423
62435341452433505
7163205044100234
oct22774634022761
94553044530125
101305241200113
114636056a2434
12190b6a778895
1396111c07196
14472616b541b
1523e44123578
hex12fe67025f1

1305241200113 has 2 divisors, whose sum is σ = 1305241200114. Its totient is φ = 1305241200112.

The previous prime is 1305241200041. The next prime is 1305241200139. The reversal of 1305241200113 is 3110021425031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 848255736064 + 456985464049 = 921008^2 + 676007^2 .

It is a cyclic number.

It is not a de Polignac number, because 1305241200113 - 224 = 1305224422897 is a prime.

It is a super-2 number, since 2×13052412001132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1305241200013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652620600056 + 652620600057.

It is an arithmetic number, because the mean of its divisors is an integer number (652620600057).

Almost surely, 21305241200113 is an apocalyptic number.

It is an amenable number.

1305241200113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1305241200113 is an equidigital number, since it uses as much as digits as its factorization.

1305241200113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 1305241200113 its reverse (3110021425031), we get a palindrome (4415262625144).

The spelling of 1305241200113 in words is "one trillion, three hundred five billion, two hundred forty-one million, two hundred thousand, one hundred thirteen".