Base | Representation |
---|---|
bin | 11000010100000001… |
… | …10001011001010011 |
3 | 1020200200021211012121 |
4 | 30022000301121103 |
5 | 203213014020441 |
6 | 5555120235111 |
7 | 641314422103 |
oct | 141200613123 |
9 | 36620254177 |
10 | 13052876371 |
11 | 5599010237 |
12 | 264346ba97 |
13 | 13003263b2 |
14 | 8bb7b1203 |
15 | 515de8dd1 |
hex | 30a031653 |
13052876371 has 2 divisors, whose sum is σ = 13052876372. Its totient is φ = 13052876370.
The previous prime is 13052876351. The next prime is 13052876383. The reversal of 13052876371 is 17367825031.
It is a strong prime.
It is an emirp because it is prime and its reverse (17367825031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13052876371 - 25 = 13052876339 is a prime.
It is a super-2 number, since 2×130528763712 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13052876341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6526438185 + 6526438186.
It is an arithmetic number, because the mean of its divisors is an integer number (6526438186).
Almost surely, 213052876371 is an apocalyptic number.
13052876371 is a deficient number, since it is larger than the sum of its proper divisors (1).
13052876371 is an equidigital number, since it uses as much as digits as its factorization.
13052876371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 211680, while the sum is 43.
The spelling of 13052876371 in words is "thirteen billion, fifty-two million, eight hundred seventy-six thousand, three hundred seventy-one".
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