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13053033151 = 88314782597
BaseRepresentation
bin11000010100000010…
…10111101010111111
31020200200120210021021
430022001113222333
5203213034030101
65555123445011
7641315644144
oct141201275277
936620523237
1013053033151
115599108004
122643526767
13130037c872
148bb8123cb
15515e2a5a1
hex30a057abf

13053033151 has 4 divisors (see below), whose sum is σ = 13067816632. Its totient is φ = 13038249672.

The previous prime is 13053033121. The next prime is 13053033157. The reversal of 13053033151 is 15133035031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13053033151 is a prime.

It is a super-2 number, since 2×130530331512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13053033157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7390416 + ... + 7392181.

It is an arithmetic number, because the mean of its divisors is an integer number (3266954158).

Almost surely, 213053033151 is an apocalyptic number.

13053033151 is a deficient number, since it is larger than the sum of its proper divisors (14783481).

13053033151 is an equidigital number, since it uses as much as digits as its factorization.

13053033151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14783480.

The product of its (nonzero) digits is 2025, while the sum is 25.

Adding to 13053033151 its reverse (15133035031), we get a palindrome (28186068182).

The spelling of 13053033151 in words is "thirteen billion, fifty-three million, thirty-three thousand, one hundred fifty-one".

Divisors: 1 883 14782597 13053033151