Base | Representation |
---|---|
bin | 10010111111101010101… |
… | …101111011111111001111 |
3 | 11121210020111200220000122 |
4 | 102333222231323333033 |
5 | 132341240112021143 |
6 | 2435352535415155 |
7 | 163206605305424 |
oct | 22775255737717 |
9 | 4553214626018 |
10 | 1305313001423 |
11 | 463642183862 |
12 | 190b8a8244bb |
13 | 96123a56872 |
14 | 4726b045d4b |
15 | 23e4a5a7c68 |
hex | 12feab7bfcf |
1305313001423 has 2 divisors, whose sum is σ = 1305313001424. Its totient is φ = 1305313001422.
The previous prime is 1305313001411. The next prime is 1305313001477. The reversal of 1305313001423 is 3241003135031.
It is a weak prime.
It is an emirp because it is prime and its reverse (3241003135031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1305313001423 - 218 = 1305312739279 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1305313001392 and 1305313001401.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1305313009423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652656500711 + 652656500712.
It is an arithmetic number, because the mean of its divisors is an integer number (652656500712).
Almost surely, 21305313001423 is an apocalyptic number.
1305313001423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305313001423 is an equidigital number, since it uses as much as digits as its factorization.
1305313001423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 26.
Adding to 1305313001423 its reverse (3241003135031), we get a palindrome (4546316136454).
The spelling of 1305313001423 in words is "one trillion, three hundred five billion, three hundred thirteen million, one thousand, four hundred twenty-three".
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