Base | Representation |
---|---|
bin | 11101101011011111100001… |
… | …010011101101000000111011 |
3 | 122010011202020122121121010221 |
4 | 131223133201103231000323 |
5 | 114102114301032201301 |
6 | 1141341344434520511 |
7 | 36331430615534200 |
oct | 3553374123550073 |
9 | 563152218547127 |
10 | 130532131131451 |
11 | 38656403070315 |
12 | 12782002736137 |
13 | 57ab186465b7a |
14 | 2433b0889bca7 |
15 | 1015690e6bda1 |
hex | 76b7e14ed03b |
130532131131451 has 24 divisors (see below), whose sum is σ = 152465019877296. Its totient is φ = 111426818328000.
The previous prime is 130532131131449. The next prime is 130532131131491. The reversal of 130532131131451 is 154131131235031.
It is not a de Polignac number, because 130532131131451 - 21 = 130532131131449 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130532131131491) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 113525805 + ... + 114669841.
It is an arithmetic number, because the mean of its divisors is an integer number (6352709161554).
Almost surely, 2130532131131451 is an apocalyptic number.
130532131131451 is a deficient number, since it is larger than the sum of its proper divisors (21932888745845).
130532131131451 is a wasteful number, since it uses less digits than its factorization.
130532131131451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1153579 (or 1153572 counting only the distinct ones).
The product of its (nonzero) digits is 16200, while the sum is 34.
Adding to 130532131131451 its reverse (154131131235031), we get a palindrome (284663262366482).
The spelling of 130532131131451 in words is "one hundred thirty trillion, five hundred thirty-two billion, one hundred thirty-one million, one hundred thirty-one thousand, four hundred fifty-one".
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