Base | Representation |
---|---|
bin | 111100110010001100… |
… | …1100100011111011111 |
3 | 110110221002200222121101 |
4 | 1321210121210133133 |
5 | 4114313030143201 |
6 | 135544412413531 |
7 | 12300511651240 |
oct | 1714431443737 |
9 | 413832628541 |
10 | 130533443551 |
11 | 503a47a9175 |
12 | 2136b4772a7 |
13 | c4035690c4 |
14 | 6464288cc7 |
15 | 35dead5d01 |
hex | 1e646647df |
130533443551 has 4 divisors (see below), whose sum is σ = 149181078352. Its totient is φ = 111885808752.
The previous prime is 130533443549. The next prime is 130533443567. The reversal of 130533443551 is 155344335031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130533443551 - 21 = 130533443549 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 130533443551.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130533443251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9323817390 + ... + 9323817403.
It is an arithmetic number, because the mean of its divisors is an integer number (37295269588).
Almost surely, 2130533443551 is an apocalyptic number.
130533443551 is a deficient number, since it is larger than the sum of its proper divisors (18647634801).
130533443551 is an equidigital number, since it uses as much as digits as its factorization.
130533443551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18647634800.
The product of its (nonzero) digits is 162000, while the sum is 37.
Adding to 130533443551 its reverse (155344335031), we get a palindrome (285877778582).
The spelling of 130533443551 in words is "one hundred thirty billion, five hundred thirty-three million, four hundred forty-three thousand, five hundred fifty-one".
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