Base | Representation |
---|---|
bin | 1011110111110011100001… |
… | …0111010010011101010011 |
3 | 1201012212222111021102001221 |
4 | 2331330320113102131103 |
5 | 3202331230404212210 |
6 | 43432343214505511 |
7 | 2515034132564602 |
oct | 275747027223523 |
9 | 51185874242057 |
10 | 13053351241555 |
11 | 4182993526169 |
12 | 15699b0b05297 |
13 | 738c05b0b9c1 |
14 | 331add86da39 |
15 | 1798333521da |
hex | bdf385d2753 |
13053351241555 has 4 divisors (see below), whose sum is σ = 15664021489872. Its totient is φ = 10442680993240.
The previous prime is 13053351241487. The next prime is 13053351241583. The reversal of 13053351241555 is 55514215335031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13053351241555 - 217 = 13053351110483 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1305335124151 + ... + 1305335124160.
It is an arithmetic number, because the mean of its divisors is an integer number (3916005372468).
Almost surely, 213053351241555 is an apocalyptic number.
13053351241555 is a deficient number, since it is larger than the sum of its proper divisors (2610670248317).
13053351241555 is an equidigital number, since it uses as much as digits as its factorization.
13053351241555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2610670248316.
The product of its (nonzero) digits is 675000, while the sum is 43.
Adding to 13053351241555 its reverse (55514215335031), we get a palindrome (68567566576586).
The spelling of 13053351241555 in words is "thirteen trillion, fifty-three billion, three hundred fifty-one million, two hundred forty-one thousand, five hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •