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13053351241555 = 52610670248311
BaseRepresentation
bin1011110111110011100001…
…0111010010011101010011
31201012212222111021102001221
42331330320113102131103
53202331230404212210
643432343214505511
72515034132564602
oct275747027223523
951185874242057
1013053351241555
114182993526169
1215699b0b05297
13738c05b0b9c1
14331add86da39
151798333521da
hexbdf385d2753

13053351241555 has 4 divisors (see below), whose sum is σ = 15664021489872. Its totient is φ = 10442680993240.

The previous prime is 13053351241487. The next prime is 13053351241583. The reversal of 13053351241555 is 55514215335031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13053351241555 - 217 = 13053351110483 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1305335124151 + ... + 1305335124160.

It is an arithmetic number, because the mean of its divisors is an integer number (3916005372468).

Almost surely, 213053351241555 is an apocalyptic number.

13053351241555 is a deficient number, since it is larger than the sum of its proper divisors (2610670248317).

13053351241555 is an equidigital number, since it uses as much as digits as its factorization.

13053351241555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2610670248316.

The product of its (nonzero) digits is 675000, while the sum is 43.

Adding to 13053351241555 its reverse (55514215335031), we get a palindrome (68567566576586).

The spelling of 13053351241555 in words is "thirteen trillion, fifty-three billion, three hundred fifty-one million, two hundred forty-one thousand, five hundred fifty-five".

Divisors: 1 5 2610670248311 13053351241555