Base | Representation |
---|---|
bin | 1011110111110011100001… |
… | …0111010010100101000011 |
3 | 1201012212222111021102202022 |
4 | 2331330320113102211003 |
5 | 3202331230404221201 |
6 | 43432343214512055 |
7 | 2515034132566211 |
oct | 275747027224503 |
9 | 51185874242668 |
10 | 13053351242051 |
11 | 418299352657a |
12 | 15699b0b0562b |
13 | 738c05b0bcb3 |
14 | 331add86dcb1 |
15 | 17983335241b |
hex | bdf385d2943 |
13053351242051 has 2 divisors, whose sum is σ = 13053351242052. Its totient is φ = 13053351242050.
The previous prime is 13053351242021. The next prime is 13053351242101. The reversal of 13053351242051 is 15024215335031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13053351242051 - 222 = 13053347047747 is a prime.
It is not a weakly prime, because it can be changed into another prime (13053351242021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6526675621025 + 6526675621026.
It is an arithmetic number, because the mean of its divisors is an integer number (6526675621026).
Almost surely, 213053351242051 is an apocalyptic number.
13053351242051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13053351242051 is an equidigital number, since it uses as much as digits as its factorization.
13053351242051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 13053351242051 its reverse (15024215335031), we get a palindrome (28077566577082).
The spelling of 13053351242051 in words is "thirteen trillion, fifty-three billion, three hundred fifty-one million, two hundred forty-two thousand, fifty-one".
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