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13053403151 = 31421077521
BaseRepresentation
bin11000010100000101…
…10010000000001111
31020200201021120210222
430022002302000033
5203213132400101
65555135421555
7641322044645
oct141202620017
936621246728
1013053403151
11559933aa98
1226436848bb
13130047c0b9
148bb8ab195
15515ea001b
hex30a0b200f

13053403151 has 4 divisors (see below), whose sum is σ = 13474480704. Its totient is φ = 12632325600.

The previous prime is 13053403133. The next prime is 13053403159. The reversal of 13053403151 is 15130435031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13053403151 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13053403151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13053403159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 210538730 + ... + 210538791.

It is an arithmetic number, because the mean of its divisors is an integer number (3368620176).

Almost surely, 213053403151 is an apocalyptic number.

13053403151 is a deficient number, since it is larger than the sum of its proper divisors (421077553).

13053403151 is an equidigital number, since it uses as much as digits as its factorization.

13053403151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 421077552.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 13053403151 its reverse (15130435031), we get a palindrome (28183838182).

The spelling of 13053403151 in words is "thirteen billion, fifty-three million, four hundred three thousand, one hundred fifty-one".

Divisors: 1 31 421077521 13053403151