Base | Representation |
---|---|
bin | 111100110010011011… |
… | …1111101111011010111 |
3 | 110110221122200211100011 |
4 | 1321210313331323113 |
5 | 4114322100141210 |
6 | 135545255301051 |
7 | 12300636460105 |
oct | 1714467757327 |
9 | 413848624304 |
10 | 130541412055 |
11 | 503a925100a |
12 | 2137207a787 |
13 | c4050c90b2 |
14 | 6465360c75 |
15 | 35e065bd8a |
hex | 1e64dfded7 |
130541412055 has 16 divisors (see below), whose sum is σ = 158067858240. Its totient is φ = 103488060928.
The previous prime is 130541412049. The next prime is 130541412143. The reversal of 130541412055 is 550214145031.
It is a cyclic number.
It is not a de Polignac number, because 130541412055 - 229 = 130004541143 is a prime.
It is a super-2 number, since 2×1305414120552 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3165549 + ... + 3206521.
It is an arithmetic number, because the mean of its divisors is an integer number (9879241140).
Almost surely, 2130541412055 is an apocalyptic number.
130541412055 is a deficient number, since it is larger than the sum of its proper divisors (27526446185).
130541412055 is a wasteful number, since it uses less digits than its factorization.
130541412055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46730.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 130541412055 its reverse (550214145031), we get a palindrome (680755557086).
The spelling of 130541412055 in words is "one hundred thirty billion, five hundred forty-one million, four hundred twelve thousand, fifty-five".
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