Base | Representation |
---|---|
bin | 10010111111110001110… |
… | …010001010100010010111 |
3 | 11121210112202202210020111 |
4 | 102333301302022202113 |
5 | 132342010434100403 |
6 | 2435412412343451 |
7 | 163212545043412 |
oct | 22776162124227 |
9 | 4553482683214 |
10 | 1305431550103 |
11 | 4636a309417a |
12 | 191002474b87 |
13 | 96142493005 |
14 | 4727caa4b79 |
15 | 23e55bc356d |
hex | 12ff1c8a897 |
1305431550103 has 2 divisors, whose sum is σ = 1305431550104. Its totient is φ = 1305431550102.
The previous prime is 1305431550097. The next prime is 1305431550139. The reversal of 1305431550103 is 3010551345031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1305431550103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1305431550173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652715775051 + 652715775052.
It is an arithmetic number, because the mean of its divisors is an integer number (652715775052).
Almost surely, 21305431550103 is an apocalyptic number.
1305431550103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305431550103 is an equidigital number, since it uses as much as digits as its factorization.
1305431550103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 1305431550103 its reverse (3010551345031), we get a palindrome (4315982895134).
The spelling of 1305431550103 in words is "one trillion, three hundred five billion, four hundred thirty-one million, five hundred fifty thousand, one hundred three".
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