130543222254401 has 4 divisors (see below), whose sum is σ = 142410787913904. Its totient is φ = 118675656594900.

The previous prime is 130543222254397. The next prime is 130543222254421. The reversal of 130543222254401 is 104452222345031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130543222254401 - 2² = 130543222254397 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130543222254421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5933782829735 + ... + 5933782829756.

It is an arithmetic number, because the mean of its divisors is an integer number (35602696978476).

Almost surely, 2^{130543222254401} is an apocalyptic number.

130543222254401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

130543222254401 is a deficient number, since it is larger than the sum of its proper divisors (11867565659503).

130543222254401 is a wasteful number, since it uses less digits than its factorization.

130543222254401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11867565659502.

The product of its (nonzero) digits is 230400, while the sum is 38.

Adding to 130543222254401 its reverse (104452222345031), we get a palindrome (234995444599432).

The spelling of 130543222254401 in words is "one hundred thirty trillion, five hundred forty-three billion, two hundred twenty-two million, two hundred fifty-four thousand, four hundred one".