Base | Representation |
---|---|
bin | 111100110010011111… |
… | …1010101111100000011 |
3 | 110110221210100001101221 |
4 | 1321210333111330003 |
5 | 4114323044023121 |
6 | 135545404535511 |
7 | 12300662061523 |
oct | 1714477257403 |
9 | 413853301357 |
10 | 130543345411 |
11 | 503aa351626 |
12 | 21372851597 |
13 | c4056250ab |
14 | 6465705683 |
15 | 35e08deb41 |
hex | 1e64fd5f03 |
130543345411 has 2 divisors, whose sum is σ = 130543345412. Its totient is φ = 130543345410.
The previous prime is 130543345409. The next prime is 130543345531. The reversal of 130543345411 is 114543345031.
It is a weak prime.
It is an emirp because it is prime and its reverse (114543345031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130543345411 - 21 = 130543345409 is a prime.
Together with 130543345409, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (130543345211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65271672705 + 65271672706.
It is an arithmetic number, because the mean of its divisors is an integer number (65271672706).
Almost surely, 2130543345411 is an apocalyptic number.
130543345411 is a deficient number, since it is larger than the sum of its proper divisors (1).
130543345411 is an equidigital number, since it uses as much as digits as its factorization.
130543345411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
The spelling of 130543345411 in words is "one hundred thirty billion, five hundred forty-three million, three hundred forty-five thousand, four hundred eleven".
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