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13054353353 = 47277752199
BaseRepresentation
bin11000010100001100…
…11001111111001001
31020200210001212020122
430022012121333021
5203213403301403
65555212033025
7641333113136
oct141206317711
936623055218
1013054353353
115599929988
122643a62775
131300722752
148bba7758d
155160db838
hex30a199fc9

13054353353 has 4 divisors (see below), whose sum is σ = 13332105600. Its totient is φ = 12776601108.

The previous prime is 13054353349. The next prime is 13054353371. The reversal of 13054353353 is 35335345031.

13054353353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35335345031 = 75047906433.

It is a cyclic number.

It is not a de Polignac number, because 13054353353 - 22 = 13054353349 is a prime.

It is a super-2 number, since 2×130543533532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13054353253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138876053 + ... + 138876146.

It is an arithmetic number, because the mean of its divisors is an integer number (3333026400).

Almost surely, 213054353353 is an apocalyptic number.

It is an amenable number.

13054353353 is a deficient number, since it is larger than the sum of its proper divisors (277752247).

13054353353 is an equidigital number, since it uses as much as digits as its factorization.

13054353353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 277752246.

The product of its (nonzero) digits is 121500, while the sum is 35.

Adding to 13054353353 its reverse (35335345031), we get a palindrome (48389698384).

The spelling of 13054353353 in words is "thirteen billion, fifty-four million, three hundred fifty-three thousand, three hundred fifty-three".

Divisors: 1 47 277752199 13054353353