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1305440400130 = 25130544040013
BaseRepresentation
bin10010111111110010010…
…011111011001100000010
311121210120101102102012021
4102333302103323030002
5132342020220301010
62435413330152054
7163213013213266
oct22776223731402
94553511372167
101305440400130
114636a8089349
1219100542262a
1396144271309
144727dd2a0a6
1523e568708da
hex12ff24fb302

1305440400130 has 8 divisors (see below), whose sum is σ = 2349792720252. Its totient is φ = 522176160048.

The previous prime is 1305440400127. The next prime is 1305440400151. The reversal of 1305440400130 is 310040445031.

It can be written as a sum of positive squares in 2 ways, for example, as 1128844625841 + 176595774289 = 1062471^2 + 420233^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1305440400095 and 1305440400104.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65272019997 + ... + 65272020016.

Almost surely, 21305440400130 is an apocalyptic number.

1305440400130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1305440400130 is a deficient number, since it is larger than the sum of its proper divisors (1044352320122).

1305440400130 is a wasteful number, since it uses less digits than its factorization.

1305440400130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130544040020.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 1305440400130 its reverse (310040445031), we get a palindrome (1615480845161).

The spelling of 1305440400130 in words is "one trillion, three hundred five billion, four hundred forty million, four hundred thousand, one hundred thirty".

Divisors: 1 2 5 10 130544040013 261088080026 652720200065 1305440400130