Base | Representation |
---|---|
bin | 1011110111110111101011… |
… | …0000001000101010101001 |
3 | 1201012222212010002210210220 |
4 | 2331331322300020222221 |
5 | 3202341021023120210 |
6 | 43433045523400253 |
7 | 2515103546035416 |
oct | 275757260105251 |
9 | 51188763083726 |
10 | 13054465051305 |
11 | 4183405212997 |
12 | 156a061b23089 |
13 | 7390527b6322 |
14 | 331ba776510d |
15 | 17989b014c70 |
hex | bdf7ac08aa9 |
13054465051305 has 32 divisors (see below), whose sum is σ = 21455962391424. Its totient is φ = 6772850712576.
The previous prime is 13054465051291. The next prime is 13054465051349. The reversal of 13054465051305 is 50315056445031.
It is a happy number.
It is not a de Polignac number, because 13054465051305 - 28 = 13054465051049 is a prime.
It is a super-3 number, since 3×130544650513053 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 415662 + ... + 5126568.
It is an arithmetic number, because the mean of its divisors is an integer number (670498824732).
Almost surely, 213054465051305 is an apocalyptic number.
13054465051305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13054465051305 is a deficient number, since it is larger than the sum of its proper divisors (8401497340119).
13054465051305 is a wasteful number, since it uses less digits than its factorization.
13054465051305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4715945.
The product of its (nonzero) digits is 540000, while the sum is 42.
The spelling of 13054465051305 in words is "thirteen trillion, fifty-four billion, four hundred sixty-five million, fifty-one thousand, three hundred five".
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