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130547531501 is a prime number
BaseRepresentation
bin111100110010100111…
…1010011111011101101
3110110222002012201122022
41321211033103323231
54114330132002001
6135550034355525
712301042465052
oct1714517237355
9413862181568
10130547531501
1150401750702
122137412bba5
13c40645c57a
1464660b5029
1535e0e6a11b
hex1e653d3eed

130547531501 has 2 divisors, whose sum is σ = 130547531502. Its totient is φ = 130547531500.

The previous prime is 130547531489. The next prime is 130547531507. The reversal of 130547531501 is 105135745031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101713793476 + 28833738025 = 318926^2 + 169805^2 .

It is an emirp because it is prime and its reverse (105135745031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130547531501 - 226 = 130480422637 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130547531507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65273765750 + 65273765751.

It is an arithmetic number, because the mean of its divisors is an integer number (65273765751).

Almost surely, 2130547531501 is an apocalyptic number.

It is an amenable number.

130547531501 is a deficient number, since it is larger than the sum of its proper divisors (1).

130547531501 is an equidigital number, since it uses as much as digits as its factorization.

130547531501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31500, while the sum is 35.

The spelling of 130547531501 in words is "one hundred thirty billion, five hundred forty-seven million, five hundred thirty-one thousand, five hundred one".