Search a number
-
+
130551132419 is a prime number
BaseRepresentation
bin111100110010101110…
…1000011000100000011
3110110222022222200011122
41321211131003010003
54114332042214134
6135550243502455
712301115213261
oct1714535030403
9413868880148
10130551132419
1150403790074
1221375387a2b
13c4071205a6
146466771431
1535e142c02e
hex1e65743103

130551132419 has 2 divisors, whose sum is σ = 130551132420. Its totient is φ = 130551132418.

The previous prime is 130551132403. The next prime is 130551132431. The reversal of 130551132419 is 914231155031.

It is a strong prime.

It is an emirp because it is prime and its reverse (914231155031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130551132419 - 24 = 130551132403 is a prime.

It is a super-2 number, since 2×1305511324192 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130551132479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65275566209 + 65275566210.

It is an arithmetic number, because the mean of its divisors is an integer number (65275566210).

Almost surely, 2130551132419 is an apocalyptic number.

130551132419 is a deficient number, since it is larger than the sum of its proper divisors (1).

130551132419 is an equidigital number, since it uses as much as digits as its factorization.

130551132419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16200, while the sum is 35.

The spelling of 130551132419 in words is "one hundred thirty billion, five hundred fifty-one million, one hundred thirty-two thousand, four hundred nineteen".