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13055124211 = 17767948483
BaseRepresentation
bin11000010100010010…
…10110001011110011
31020200211112000122221
430022021112023303
5203214102433321
65555240341511
7641342503423
oct141211261363
936624460587
1013055124211
11559a306058
122644174897
13130093258c
148bbbd8483
155161dee41
hex30a2562f3

13055124211 has 4 divisors (see below), whose sum is σ = 13823072712. Its totient is φ = 12287175712.

The previous prime is 13055124193. The next prime is 13055124227. The reversal of 13055124211 is 11242155031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11242155031 = 15771606083.

It is a cyclic number.

It is not a de Polignac number, because 13055124211 - 25 = 13055124179 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13055124611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 383974225 + ... + 383974258.

It is an arithmetic number, because the mean of its divisors is an integer number (3455768178).

Almost surely, 213055124211 is an apocalyptic number.

13055124211 is a deficient number, since it is larger than the sum of its proper divisors (767948501).

13055124211 is an equidigital number, since it uses as much as digits as its factorization.

13055124211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 767948500.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 13055124211 its reverse (11242155031), we get a palindrome (24297279242).

The spelling of 13055124211 in words is "thirteen billion, fifty-five million, one hundred twenty-four thousand, two hundred eleven".

Divisors: 1 17 767948483 13055124211