Base | Representation |
---|---|
bin | 11000010100010100… |
… | …00100000101101001 |
3 | 1020200211212120120201 |
4 | 30022022010011221 |
5 | 203214124442413 |
6 | 5555244352201 |
7 | 641344215535 |
oct | 141212040551 |
9 | 36624776521 |
10 | 13055312233 |
11 | 559a424347 |
12 | 2644245661 |
13 | 130099a032 |
14 | 8bbc46bc5 |
15 | 51622a9dd |
hex | 30a284169 |
13055312233 has 4 divisors (see below), whose sum is σ = 13622934528. Its totient is φ = 12487689940.
The previous prime is 13055312219. The next prime is 13055312251. The reversal of 13055312233 is 33221355031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13055312233 - 229 = 12518441321 is a prime.
It is a super-2 number, since 2×130553122332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13055312273) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 283811113 + ... + 283811158.
It is an arithmetic number, because the mean of its divisors is an integer number (3405733632).
Almost surely, 213055312233 is an apocalyptic number.
It is an amenable number.
13055312233 is a deficient number, since it is larger than the sum of its proper divisors (567622295).
13055312233 is an equidigital number, since it uses as much as digits as its factorization.
13055312233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 567622294.
The product of its (nonzero) digits is 8100, while the sum is 28.
Adding to 13055312233 its reverse (33221355031), we get a palindrome (46276667264).
The spelling of 13055312233 in words is "thirteen billion, fifty-five million, three hundred twelve thousand, two hundred thirty-three".
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