Base | Representation |
---|---|
bin | 111100110010110010… |
… | …0111110100011100111 |
3 | 110110222110220021121020 |
4 | 1321211210332203213 |
5 | 4114333110223421 |
6 | 135550400222223 |
7 | 12301141661511 |
oct | 1714544764347 |
9 | 413873807536 |
10 | 130553211111 |
11 | 5040497a8a4 |
12 | 2137600a973 |
13 | c40769a79b |
14 | 6466b52bb1 |
15 | 35e16dcdc6 |
hex | 1e6593e8e7 |
130553211111 has 4 divisors (see below), whose sum is σ = 174070948152. Its totient is φ = 87035474072.
The previous prime is 130553211097. The next prime is 130553211119. The reversal of 130553211111 is 111112355031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111112355031 = 3 ⋅37037451677.
It is a cyclic number.
It is not a de Polignac number, because 130553211111 - 217 = 130553080039 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130553211119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21758868516 + ... + 21758868521.
It is an arithmetic number, because the mean of its divisors is an integer number (43517737038).
Almost surely, 2130553211111 is an apocalyptic number.
130553211111 is a deficient number, since it is larger than the sum of its proper divisors (43517737041).
130553211111 is an equidigital number, since it uses as much as digits as its factorization.
130553211111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43517737040.
The product of its (nonzero) digits is 450, while the sum is 24.
Adding to 130553211111 its reverse (111112355031), we get a palindrome (241665566142).
The spelling of 130553211111 in words is "one hundred thirty billion, five hundred fifty-three million, two hundred eleven thousand, one hundred eleven".
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