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130554524381 is a prime number
BaseRepresentation
bin111100110010110100…
…1111111001011011101
3110110222120101000001212
41321211221333023131
54114333424240011
6135550444314205
712301156101341
oct1714551771335
9413876330055
10130554524381
1150405697546
1221376542965
13c407a3a478
146466db5621
1535e189c08b
hex1e65a7f2dd

130554524381 has 2 divisors, whose sum is σ = 130554524382. Its totient is φ = 130554524380.

The previous prime is 130554524377. The next prime is 130554524417. The reversal of 130554524381 is 183425455031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96665028100 + 33889496281 = 310910^2 + 184091^2 .

It is a cyclic number.

It is not a de Polignac number, because 130554524381 - 22 = 130554524377 is a prime.

It is a super-2 number, since 2×1305545243812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130554524371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65277262190 + 65277262191.

It is an arithmetic number, because the mean of its divisors is an integer number (65277262191).

Almost surely, 2130554524381 is an apocalyptic number.

It is an amenable number.

130554524381 is a deficient number, since it is larger than the sum of its proper divisors (1).

130554524381 is an equidigital number, since it uses as much as digits as its factorization.

130554524381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288000, while the sum is 41.

The spelling of 130554524381 in words is "one hundred thirty billion, five hundred fifty-four million, five hundred twenty-four thousand, three hundred eighty-one".