Base | Representation |
---|---|
bin | 10010111111111001000… |
… | …011100011111110010101 |
3 | 11121210212021100002100121 |
4 | 102333321003203332111 |
5 | 132342233202120003 |
6 | 2435432451311541 |
7 | 163215556041040 |
oct | 22777103437625 |
9 | 4553767302317 |
10 | 1305553551253 |
11 | 463755a42476 |
12 | 1910372ab5b1 |
13 | 9616183aa43 |
14 | 47290d81c57 |
15 | 23e61771cbd |
hex | 12ff90e3f95 |
1305553551253 has 4 divisors (see below), whose sum is σ = 1492061201440. Its totient is φ = 1119045901068.
The previous prime is 1305553551241. The next prime is 1305553551283. The reversal of 1305553551253 is 3521553555031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1305553551253 - 25 = 1305553551221 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1305553551283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93253825083 + ... + 93253825096.
It is an arithmetic number, because the mean of its divisors is an integer number (373015300360).
Almost surely, 21305553551253 is an apocalyptic number.
It is an amenable number.
1305553551253 is a deficient number, since it is larger than the sum of its proper divisors (186507650187).
1305553551253 is an equidigital number, since it uses as much as digits as its factorization.
1305553551253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 186507650186.
The product of its (nonzero) digits is 843750, while the sum is 43.
The spelling of 1305553551253 in words is "one trillion, three hundred five billion, five hundred fifty-three million, five hundred fifty-one thousand, two hundred fifty-three".
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