Search a number
-
+
1305616451017 is a prime number
BaseRepresentation
bin10010111111111100110…
…011100000010111001001
311121211000122200201121111
4102333330303200113021
5132342400302413032
62435443015410321
7163220251503214
oct22777463402711
94554018621544
101305616451017
114637884a3a4a
121910543839a1
1396171891838
144729947677b
1523e67048c47
hex12ffcce05c9

1305616451017 has 2 divisors, whose sum is σ = 1305616451018. Its totient is φ = 1305616451016.

The previous prime is 1305616451011. The next prime is 1305616451059. The reversal of 1305616451017 is 7101546165031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1280385034681 + 25231416336 = 1131541^2 + 158844^2 .

It is an emirp because it is prime and its reverse (7101546165031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1305616451017 is a prime.

It is not a weakly prime, because it can be changed into another prime (1305616451011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652808225508 + 652808225509.

It is an arithmetic number, because the mean of its divisors is an integer number (652808225509).

Almost surely, 21305616451017 is an apocalyptic number.

It is an amenable number.

1305616451017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1305616451017 is an equidigital number, since it uses as much as digits as its factorization.

1305616451017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75600, while the sum is 40.

The spelling of 1305616451017 in words is "one trillion, three hundred five billion, six hundred sixteen million, four hundred fifty-one thousand, seventeen".