Base | Representation |
---|---|
bin | 1011111000000000001100… |
… | …1101101010000010100001 |
3 | 1201020012202200002102102011 |
4 | 2332000003031222002201 |
5 | 3202410213122212203 |
6 | 43434105030152521 |
7 | 2515214355666343 |
oct | 276000315520241 |
9 | 51205680072364 |
10 | 13056754491553 |
11 | 418437a581273 |
12 | 156a5a07b2741 |
13 | 739328c01bb6 |
14 | 331d43845293 |
15 | 179981eec76d |
hex | be00336a0a1 |
13056754491553 has 2 divisors, whose sum is σ = 13056754491554. Its totient is φ = 13056754491552.
The previous prime is 13056754491533. The next prime is 13056754491581. The reversal of 13056754491553 is 35519445765031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11508703432704 + 1548051058849 = 3392448^2 + 1244207^2 .
It is a cyclic number.
It is not a de Polignac number, because 13056754491553 - 225 = 13056720937121 is a prime.
It is not a weakly prime, because it can be changed into another prime (13056754491533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6528377245776 + 6528377245777.
It is an arithmetic number, because the mean of its divisors is an integer number (6528377245777).
Almost surely, 213056754491553 is an apocalyptic number.
It is an amenable number.
13056754491553 is a deficient number, since it is larger than the sum of its proper divisors (1).
13056754491553 is an equidigital number, since it uses as much as digits as its factorization.
13056754491553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34020000, while the sum is 58.
The spelling of 13056754491553 in words is "thirteen trillion, fifty-six billion, seven hundred fifty-four million, four hundred ninety-one thousand, five hundred fifty-three".
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