Base | Representation |
---|---|
bin | 111100110100000011… |
… | …1111111000010011001 |
3 | 110111002110022021010020 |
4 | 1321220013333002121 |
5 | 4114430030130203 |
6 | 135554524141053 |
7 | 12302201124126 |
oct | 1715007770231 |
9 | 414073267106 |
10 | 130595942553 |
11 | 5042700663a |
12 | 21388397789 |
13 | c4134ac66b |
14 | 646c6b774d |
15 | 35e532e153 |
hex | 1e681ff099 |
130595942553 has 24 divisors (see below), whose sum is σ = 181117909728. Its totient is φ = 83690050176.
The previous prime is 130595942473. The next prime is 130595942579. The reversal of 130595942553 is 355249595031.
It is a happy number.
It is not a de Polignac number, because 130595942553 - 28 = 130595942297 is a prime.
It is a super-2 number, since 2×1305959425532 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130595942496 and 130595942505.
It is not an unprimeable number, because it can be changed into a prime (130595942593) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 149325 + ... + 532437.
It is an arithmetic number, because the mean of its divisors is an integer number (7546579572).
Almost surely, 2130595942553 is an apocalyptic number.
It is an amenable number.
130595942553 is a deficient number, since it is larger than the sum of its proper divisors (50521967175).
130595942553 is an equidigital number, since it uses as much as digits as its factorization.
130595942553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 383273 (or 383236 counting only the distinct ones).
The product of its (nonzero) digits is 3645000, while the sum is 51.
The spelling of 130595942553 in words is "one hundred thirty billion, five hundred ninety-five million, nine hundred forty-two thousand, five hundred fifty-three".
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