Base | Representation |
---|---|
bin | 1011111000001100011100… |
… | …1111101010000101000101 |
3 | 1201020112020212122202111220 |
4 | 2332003013033222011011 |
5 | 3202433432044202331 |
6 | 43435411233550553 |
7 | 2515362022560051 |
oct | 276030717520505 |
9 | 51215225582456 |
10 | 13060043350341 |
11 | 4185807aa6589 |
12 | 156b15a115459 |
13 | 7397313b30a0 |
14 | 332176560c61 |
15 | 179ac5aee296 |
hex | be0c73ea145 |
13060043350341 has 32 divisors (see below), whose sum is σ = 18833228494080. Its totient is φ = 8002545237504.
The previous prime is 13060043350309. The next prime is 13060043350351. The reversal of 13060043350341 is 14305334006031.
13060043350341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13060043350341 - 25 = 13060043350309 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13060043350351) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 21122115 + ... + 21731631.
It is an arithmetic number, because the mean of its divisors is an integer number (588538390440).
Almost surely, 213060043350341 is an apocalyptic number.
It is an amenable number.
13060043350341 is a deficient number, since it is larger than the sum of its proper divisors (5773185143739).
13060043350341 is a wasteful number, since it uses less digits than its factorization.
13060043350341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 611885.
The product of its (nonzero) digits is 38880, while the sum is 33.
Adding to 13060043350341 its reverse (14305334006031), we get a palindrome (27365377356372).
The spelling of 13060043350341 in words is "thirteen trillion, sixty billion, forty-three million, three hundred fifty thousand, three hundred forty-one".
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