Base | Representation |
---|---|
bin | 10011000000010101101… |
… | …101100101111101000111 |
3 | 11121212002210000020211001 |
4 | 103000111231211331013 |
5 | 132344224242101323 |
6 | 2435552304154131 |
7 | 163233514435441 |
oct | 23002555457507 |
9 | 4555083006731 |
10 | 1306034331463 |
11 | 463982371794 |
12 | 191150308947 |
13 | 9620a323884 |
14 | 472d8b73491 |
15 | 23e8da903ad |
hex | 13015b65f47 |
1306034331463 has 4 divisors (see below), whose sum is σ = 1307045978248. Its totient is φ = 1305022684680.
The previous prime is 1306034331439. The next prime is 1306034331499. The reversal of 1306034331463 is 3641334306031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1306034331463 - 213 = 1306034323271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1306034331163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505821456 + ... + 505824037.
It is an arithmetic number, because the mean of its divisors is an integer number (326761494562).
Almost surely, 21306034331463 is an apocalyptic number.
1306034331463 is a deficient number, since it is larger than the sum of its proper divisors (1011646785).
1306034331463 is a wasteful number, since it uses less digits than its factorization.
1306034331463 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1011646784.
The product of its (nonzero) digits is 139968, while the sum is 37.
Adding to 1306034331463 its reverse (3641334306031), we get a palindrome (4947368637494).
The spelling of 1306034331463 in words is "one trillion, three hundred six billion, thirty-four million, three hundred thirty-one thousand, four hundred sixty-three".
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