Base | Representation |
---|---|
bin | 10011000000010111101… |
… | …000010100110111010101 |
3 | 11121212012000112211211221 |
4 | 103000113220110313111 |
5 | 132344311011131143 |
6 | 2435555413530341 |
7 | 163234355056363 |
oct | 23002750246725 |
9 | 4555160484757 |
10 | 1306066505173 |
11 | 463999547331 |
12 | 19115b0439b1 |
13 | 96213baa081 |
14 | 472dd14a633 |
15 | 23e917e82ed |
hex | 13017a14dd5 |
1306066505173 has 2 divisors, whose sum is σ = 1306066505174. Its totient is φ = 1306066505172.
The previous prime is 1306066505141. The next prime is 1306066505207. The reversal of 1306066505173 is 3715056606031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1246511959729 + 59554545444 = 1116473^2 + 244038^2 .
It is a cyclic number.
It is not a de Polignac number, because 1306066505173 - 25 = 1306066505141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1306066505113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653033252586 + 653033252587.
It is an arithmetic number, because the mean of its divisors is an integer number (653033252587).
Almost surely, 21306066505173 is an apocalyptic number.
It is an amenable number.
1306066505173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1306066505173 is an equidigital number, since it uses as much as digits as its factorization.
1306066505173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 340200, while the sum is 43.
The spelling of 1306066505173 in words is "one trillion, three hundred six billion, sixty-six million, five hundred five thousand, one hundred seventy-three".
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