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1306136425211 is a prime number
BaseRepresentation
bin10011000000011011110…
…011000011001011111011
311121212100220010011002222
4103000123303003023323
5132344431411101321
62440010352314255
7163236164301032
oct23003363031373
94555326104088
101306136425211
11463a24a63292
1219117a54298b
139622551b387
144730854b719
1523e97a0a3ab
hex1301bcc32fb

1306136425211 has 2 divisors, whose sum is σ = 1306136425212. Its totient is φ = 1306136425210.

The previous prime is 1306136425183. The next prime is 1306136425213. The reversal of 1306136425211 is 1125246316031.

It is a strong prime.

It is an emirp because it is prime and its reverse (1125246316031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1306136425211 - 230 = 1305062683387 is a prime.

It is a super-2 number, since 2×13061364252112 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 1306136425213, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1306136425213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653068212605 + 653068212606.

It is an arithmetic number, because the mean of its divisors is an integer number (653068212606).

Almost surely, 21306136425211 is an apocalyptic number.

1306136425211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1306136425211 is an equidigital number, since it uses as much as digits as its factorization.

1306136425211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 1306136425211 in words is "one trillion, three hundred six billion, one hundred thirty-six million, four hundred twenty-five thousand, two hundred eleven".