Base | Representation |
---|---|
bin | 10011000000101100111… |
… | …010000000110011011101 |
3 | 11121220002220020012010010 |
4 | 103000230322000303131 |
5 | 132401023401310013 |
6 | 2440055044433433 |
7 | 163246251133215 |
oct | 23005472006335 |
9 | 4556086205103 |
10 | 1306423463133 |
11 | 464061a94108 |
12 | 19123a6a8879 |
13 | 9626cb2b2b9 |
14 | 47334709245 |
15 | 23eb2d087c3 |
hex | 1302ce80cdd |
1306423463133 has 4 divisors (see below), whose sum is σ = 1741897950848. Its totient is φ = 870948975420.
The previous prime is 1306423463123. The next prime is 1306423463183. The reversal of 1306423463133 is 3313643246031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1306423463133 - 24 = 1306423463117 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1306423463091 and 1306423463100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1306423463123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217737243853 + ... + 217737243858.
It is an arithmetic number, because the mean of its divisors is an integer number (435474487712).
Almost surely, 21306423463133 is an apocalyptic number.
It is an amenable number.
1306423463133 is a deficient number, since it is larger than the sum of its proper divisors (435474487715).
1306423463133 is an equidigital number, since it uses as much as digits as its factorization.
1306423463133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 435474487714.
The product of its (nonzero) digits is 279936, while the sum is 39.
The spelling of 1306423463133 in words is "one trillion, three hundred six billion, four hundred twenty-three million, four hundred sixty-three thousand, one hundred thirty-three".
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