Base | Representation |
---|---|
bin | 11000010101011010… |
… | …10110101100001111 |
3 | 1020201111021120220011 |
4 | 30022231112230033 |
5 | 203224012012341 |
6 | 10000214534051 |
7 | 641515646221 |
oct | 141255265417 |
9 | 36644246804 |
10 | 13064563471 |
11 | 55a46729a3 |
12 | 2647367327 |
13 | 1302888b3b |
14 | 8bd174411 |
15 | 516e56b81 |
hex | 30ab56b0f |
13064563471 has 2 divisors, whose sum is σ = 13064563472. Its totient is φ = 13064563470.
The previous prime is 13064563439. The next prime is 13064563489. The reversal of 13064563471 is 17436546031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13064563471 - 25 = 13064563439 is a prime.
It is a super-3 number, since 3×130645634713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13064560471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6532281735 + 6532281736.
It is an arithmetic number, because the mean of its divisors is an integer number (6532281736).
Almost surely, 213064563471 is an apocalyptic number.
13064563471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13064563471 is an equidigital number, since it uses as much as digits as its factorization.
13064563471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 40.
The spelling of 13064563471 in words is "thirteen billion, sixty-four million, five hundred sixty-three thousand, four hundred seventy-one".
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