Base | Representation |
---|---|
bin | 1011111000011101100010… |
… | …1100100101001011010111 |
3 | 1201020222002121100012221110 |
4 | 2332013120230211023113 |
5 | 3203022331031044112 |
6 | 43441450401350103 |
7 | 2515613511112500 |
oct | 276073054451327 |
9 | 51228077305843 |
10 | 13064631112407 |
11 | 418775173a086 |
12 | 157001a638333 |
13 | 739cb2a06cb4 |
14 | 33248d993ba7 |
15 | 179c9377613c |
hex | be1d8b252d7 |
13064631112407 has 96 divisors (see below), whose sum is σ = 21233787773184. Its totient is φ = 7117481280000.
The previous prime is 13064631112369. The next prime is 13064631112417. The reversal of 13064631112407 is 70421113646031.
It is not a de Polignac number, because 13064631112407 - 26 = 13064631112343 is a prime.
It is a super-2 number, since 2×130646311124072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13064631112417) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 80095708 + ... + 80258654.
It is an arithmetic number, because the mean of its divisors is an integer number (221185289304).
Almost surely, 213064631112407 is an apocalyptic number.
13064631112407 is a deficient number, since it is larger than the sum of its proper divisors (8169156660777).
13064631112407 is a wasteful number, since it uses less digits than its factorization.
13064631112407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 163309 (or 163302 counting only the distinct ones).
The product of its (nonzero) digits is 72576, while the sum is 39.
Adding to 13064631112407 its reverse (70421113646031), we get a palindrome (83485744758438).
The spelling of 13064631112407 in words is "thirteen trillion, sixty-four billion, six hundred thirty-one million, one hundred twelve thousand, four hundred seven".
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