Base | Representation |
---|---|
bin | 10011000000111001010… |
… | …011010010001011001111 |
3 | 11121220122101112012201211 |
4 | 103000321103102023033 |
5 | 132401440120230404 |
6 | 2440131433515251 |
7 | 163254354525316 |
oct | 23007123221317 |
9 | 4556571465654 |
10 | 1306631414479 |
11 | 464159408026 |
12 | 191298272b27 |
13 | 962a3c3a831 |
14 | 4735419b27d |
15 | 23ec61d3b04 |
hex | 130394d22cf |
1306631414479 has 2 divisors, whose sum is σ = 1306631414480. Its totient is φ = 1306631414478.
The previous prime is 1306631414423. The next prime is 1306631414521. The reversal of 1306631414479 is 9744141366031.
It is a strong prime.
It is an emirp because it is prime and its reverse (9744141366031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1306631414479 - 213 = 1306631406287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1306631414579) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653315707239 + 653315707240.
It is an arithmetic number, because the mean of its divisors is an integer number (653315707240).
Almost surely, 21306631414479 is an apocalyptic number.
1306631414479 is a deficient number, since it is larger than the sum of its proper divisors (1).
1306631414479 is an equidigital number, since it uses as much as digits as its factorization.
1306631414479 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1306368, while the sum is 49.
The spelling of 1306631414479 in words is "one trillion, three hundred six billion, six hundred thirty-one million, four hundred fourteen thousand, four hundred seventy-nine".
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