Base | Representation |
---|---|
bin | 1011111000110110100101… |
… | …1000001000001010011111 |
3 | 1201021121110002112112112202 |
4 | 2332031221120020022133 |
5 | 3203130112433224203 |
6 | 43444521415522115 |
7 | 2516242215536342 |
oct | 276155130101237 |
9 | 51247402475482 |
10 | 13071353414303 |
11 | 418a591261a88 |
12 | 157139598933b |
13 | 73a814620222 |
14 | 33292a6a4459 |
15 | 17a0389d9388 |
hex | be36960829f |
13071353414303 has 2 divisors, whose sum is σ = 13071353414304. Its totient is φ = 13071353414302.
The previous prime is 13071353414233. The next prime is 13071353414347. The reversal of 13071353414303 is 30341435317031.
13071353414303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13071353414303 - 212 = 13071353410207 is a prime.
It is a super-2 number, since 2×130713534143032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13071353410303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6535676707151 + 6535676707152.
It is an arithmetic number, because the mean of its divisors is an integer number (6535676707152).
Almost surely, 213071353414303 is an apocalyptic number.
13071353414303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13071353414303 is an equidigital number, since it uses as much as digits as its factorization.
13071353414303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 38.
The spelling of 13071353414303 in words is "thirteen trillion, seventy-one billion, three hundred fifty-three million, four hundred fourteen thousand, three hundred three".
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