Search a number
-
+
130730272263595 = 526146054452719
BaseRepresentation
bin11101101110011000000011…
…011100001000110110101011
3122010212200200110010000022201
4131232120003130020312223
5114113341044144413340
61142012354043001031
736351644005423324
oct3556300334106653
9563780613100281
10130730272263595
113872244061a594
12127b449b809177
1357c3a72623424
14243d543b4144b
15101a8db10a79a
hex76e603708dab

130730272263595 has 4 divisors (see below), whose sum is σ = 156876326716320. Its totient is φ = 104584217810872.

The previous prime is 130730272263571. The next prime is 130730272263599. The reversal of 130730272263595 is 595362272037031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130730272263595 - 239 = 130180516449707 is a prime.

It is a super-2 number, since 2×1307302722635952 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130730272263599) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13073027226355 + ... + 13073027226364.

It is an arithmetic number, because the mean of its divisors is an integer number (39219081679080).

Almost surely, 2130730272263595 is an apocalyptic number.

130730272263595 is a deficient number, since it is larger than the sum of its proper divisors (26146054452725).

130730272263595 is an equidigital number, since it uses as much as digits as its factorization.

130730272263595 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26146054452724.

The product of its (nonzero) digits is 14288400, while the sum is 55.

The spelling of 130730272263595 in words is "one hundred thirty trillion, seven hundred thirty billion, two hundred seventy-two million, two hundred sixty-three thousand, five hundred ninety-five".

Divisors: 1 5 26146054452719 130730272263595