Base | Representation |
---|---|
bin | 1011111000111111001000… |
… | …1001100001000001001111 |
3 | 1201021211101000022202011121 |
4 | 2332033302021201001033 |
5 | 3203144312401000133 |
6 | 43445541230101411 |
7 | 2516353120661035 |
oct | 276176211410117 |
9 | 51254330282147 |
10 | 13073648062543 |
11 | 4190559558192 |
12 | 157191634a867 |
13 | 73aabbb40453 |
14 | 332aa733c555 |
15 | 17a1201a002d |
hex | be3f226104f |
13073648062543 has 2 divisors, whose sum is σ = 13073648062544. Its totient is φ = 13073648062542.
The previous prime is 13073648062487. The next prime is 13073648062561. The reversal of 13073648062543 is 34526084637031.
13073648062543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13073648062543 - 225 = 13073614508111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13073648066543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6536824031271 + 6536824031272.
It is an arithmetic number, because the mean of its divisors is an integer number (6536824031272).
Almost surely, 213073648062543 is an apocalyptic number.
13073648062543 is a deficient number, since it is larger than the sum of its proper divisors (1).
13073648062543 is an equidigital number, since it uses as much as digits as its factorization.
13073648062543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8709120, while the sum is 52.
The spelling of 13073648062543 in words is "thirteen trillion, seventy-three billion, six hundred forty-eight million, sixty-two thousand, five hundred forty-three".
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