Base | Representation |
---|---|
bin | 1011111001000001010110… |
… | …0010100110110111011010 |
3 | 1201021212220101121220100102 |
4 | 2332100111202212313122 |
5 | 3203202021402431100 |
6 | 43450120200535402 |
7 | 2516403621013262 |
oct | 276202542466732 |
9 | 51255811556312 |
10 | 13074241842650 |
11 | 4190833747a4a |
12 | 1571a61181562 |
13 | 73ab84b6bc21 |
14 | 332b221467a2 |
15 | 17a15738ecd5 |
hex | be4158a6dda |
13074241842650 has 48 divisors (see below), whose sum is σ = 24685734101184. Its totient is φ = 5150663105280.
The previous prime is 13074241842637. The next prime is 13074241842659. The reversal of 13074241842650 is 5624814247031.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13074241842595 and 13074241842604.
It is not an unprimeable number, because it can be changed into a prime (13074241842659) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 17397074 + ... + 18133026.
It is an arithmetic number, because the mean of its divisors is an integer number (514286127108).
Almost surely, 213074241842650 is an apocalyptic number.
13074241842650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13074241842650 is a deficient number, since it is larger than the sum of its proper divisors (11611492258534).
13074241842650 is a wasteful number, since it uses less digits than its factorization.
13074241842650 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 741335 (or 741330 counting only the distinct ones).
The product of its (nonzero) digits is 1290240, while the sum is 47.
The spelling of 13074241842650 in words is "thirteen trillion, seventy-four billion, two hundred forty-one million, eight hundred forty-two thousand, six hundred fifty".
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