Search a number
-
+
13075121128873 is a prime number
BaseRepresentation
bin1011111001000100100111…
…1100110100010110101001
31201021222011200011021021211
42332101021330310112221
53203210322002110443
643450343331033121
72516434455561046
oct276211174642651
951258150137254
1013075121128873
114191145011781
12157206773b7a1
1373ac9509232b
14332ba6c301cd
1517a1a967919d
hexbe449f345a9

13075121128873 has 2 divisors, whose sum is σ = 13075121128874. Its totient is φ = 13075121128872.

The previous prime is 13075121128829. The next prime is 13075121128891. The reversal of 13075121128873 is 37882112157031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6573906265369 + 6501214863504 = 2563963^2 + 2549748^2 .

It is a cyclic number.

It is not a de Polignac number, because 13075121128873 - 237 = 12937682175401 is a prime.

It is not a weakly prime, because it can be changed into another prime (13075121108873) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6537560564436 + 6537560564437.

It is an arithmetic number, because the mean of its divisors is an integer number (6537560564437).

Almost surely, 213075121128873 is an apocalyptic number.

It is an amenable number.

13075121128873 is a deficient number, since it is larger than the sum of its proper divisors (1).

13075121128873 is an equidigital number, since it uses as much as digits as its factorization.

13075121128873 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 564480, while the sum is 49.

The spelling of 13075121128873 in words is "thirteen trillion, seventy-five billion, one hundred twenty-one million, one hundred twenty-eight thousand, eight hundred seventy-three".