Base | Representation |
---|---|
bin | 10011000001110111011… |
… | …010011011001111111111 |
3 | 11122000100000100022201122 |
4 | 103001313122123033333 |
5 | 132411103402132142 |
6 | 2440423100501155 |
7 | 163322240063003 |
oct | 23016732331777 |
9 | 4560300308648 |
10 | 1307673474047 |
11 | 464643648886 |
12 | 19152924a7bb |
13 | 9640bab2b25 |
14 | 47412736703 |
15 | 240379221d2 |
hex | 1307769b3ff |
1307673474047 has 4 divisors (see below), whose sum is σ = 1319894721576. Its totient is φ = 1295452226520.
The previous prime is 1307673474043. The next prime is 1307673474059. The reversal of 1307673474047 is 7404743767031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1307673474047 - 22 = 1307673474043 is a prime.
It is a super-2 number, since 2×13076734740472 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1307673474047.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1307673474043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6110623604 + ... + 6110623817.
It is an arithmetic number, because the mean of its divisors is an integer number (329973680394).
Almost surely, 21307673474047 is an apocalyptic number.
1307673474047 is a deficient number, since it is larger than the sum of its proper divisors (12221247529).
1307673474047 is a wasteful number, since it uses less digits than its factorization.
1307673474047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12221247528.
The product of its (nonzero) digits is 8297856, while the sum is 53.
The spelling of 1307673474047 in words is "one trillion, three hundred seven billion, six hundred seventy-three million, four hundred seventy-four thousand, forty-seven".
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