1307733517149 has 4 divisors (see below), whose sum is σ = 1743644689536. Its totient is φ = 871822344764.

The previous prime is 1307733517147. The next prime is 1307733517199. The reversal of 1307733517149 is 9417153377031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1307733517149 - 2¹ = 1307733517147 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1307733517147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217955586189 + ... + 217955586194.

It is an arithmetic number, because the mean of its divisors is an integer number (435911172384).

Almost surely, 2^{1307733517149} is an apocalyptic number.

It is an amenable number.

1307733517149 is a deficient number, since it is larger than the sum of its proper divisors (435911172387).

1307733517149 is an equidigital number, since it uses as much as digits as its factorization.

1307733517149 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 435911172386.

The product of its (nonzero) digits is 1666980, while the sum is 51.

The spelling of 1307733517149 in words is "one trillion, three hundred seven billion, seven hundred thirty-three million, five hundred seventeen thousand, one hundred forty-nine".