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130773510347 is a prime number
BaseRepresentation
bin111100111001010110…
…1010110100011001011
3110111112211102122100012
41321302231112203023
54120311004312342
6140024310102135
712306455332364
oct1716255264313
9414484378305
10130773510347
1150508267987
122141794a94b
13c44121146c
1464880dab6b
153605c06b82
hex1e72b568cb

130773510347 has 2 divisors, whose sum is σ = 130773510348. Its totient is φ = 130773510346.

The previous prime is 130773510341. The next prime is 130773510349. The reversal of 130773510347 is 743015377031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130773510347 is a prime.

It is a super-2 number, since 2×1307735103472 (a number of 23 digits) contains 22 as substring.

Together with 130773510349, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130773510341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65386755173 + 65386755174.

It is an arithmetic number, because the mean of its divisors is an integer number (65386755174).

Almost surely, 2130773510347 is an apocalyptic number.

130773510347 is a deficient number, since it is larger than the sum of its proper divisors (1).

130773510347 is an equidigital number, since it uses as much as digits as its factorization.

130773510347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 185220, while the sum is 41.

Adding to 130773510347 its reverse (743015377031), we get a palindrome (873788887378).

The spelling of 130773510347 in words is "one hundred thirty billion, seven hundred seventy-three million, five hundred ten thousand, three hundred forty-seven".